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Thu. Sep. 14th, 2006 1:45 PM

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dohpaz

bash | Code | Comments | Grep | Sed

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I found this script online, and decided that I would modify it for my needs. As a developer, I like to know how many actual lines of code I have written--not including any comments.

It outputs in a very simple way:

Including Comments: NNN
Without Comments: NNN

One very practical, and quick, way to determine how many lines of code a project has is to pipe it through a find:

find /usr/share/php -name "*.php" -o -name "*.inc" | xargs count-code

If your code is in files of another type (i.e., .c, .h, .cpp, etc), then simply change the extensions and add more '-o -name "*.ext"' tags. If you have directories that you don't want to be counted, simple throw a "| grep -v [path/to/excluded/directory] |" inbetween the find and the xargs, and they will not be counted.

#!/bin/sh

# Count lines of C, C++, Java, or C# code, excluding comments and blank lines.

#

# Originally obtained from:

#   http://www.cs.cornell.edu/courses/cs114/2004fa/notes/lec8.html, 2004-10-15

#

# 2006-09-14: Ken Stanley

# 1. Modified the code to print out a comparison of lines between the commented

#    code and then the code if the comments were to be removed.

# 2. Now it will exclude all comments that start with a #, except if the

#    comment happens to be something like "#!/bin/sh" which is not a comment.

#

echo -en "Including comments:\t";

WITHCOMMENTS=`cat $* | wc -l`;

echo "$WITHCOMMENTS";

# Order of operation:

#       1. Strip C++ // comments

#       2. Replace @ and % with + and newline with @

#       3. Replace */ with %

#       4. Strip /* ... %

#       5. Restore newlines

#       6. Strip blank lines: [] contains a tab and space

#       7. Strip all bash-style comments

#       8. Count the remaining lines

echo -en "Without comments:\t";

WITHOUTCOMMENTS=`sed -e 's!//.*$!!' $* | tr '@%\012' '++@' | sed -e 's!\*/!%!g' | sed -e 's!/\*[^%]*%!!g' | tr @ '\012' | grep -v '^[  ]*$' | grep -v '^#[^!].*$' | wc -l`;

echo -en "$WITHOUTCOMMENTS\n\n";