So you're just gonna keep posting votes to your buggy .. worthless code snippet? You've voted something like 20 times for this script.

New revision coming up. Thanks!

=================
Matthew R. Miller
http://bluecreststudios.com
http://www.codeandcoffee.com

Also, you have an error in the code above.

$strDomain = str_replace("www.", "", strDomain);

You're missing a dollar ($) on strDomain.

You are correct. Honestly this is a very basic snippet, it could be expanded, but it definately limited.

=================
Matthew R. Miller
http://bluecreststudios.com
http://www.codeandcoffee.com

* There's a possible bug in your code. Imagine someone, who wants to check if referer is from domain awww.com. Your str_replace() will replace
"www" in $strDomain, leaving $strDomain to be "a.com" which is not correct.

* Why should you use strstr() if you want to check if one string is contained in another? You should use strpos() instead.

* Why write
if ($condition)
return true;
else
return false;

if you can simply just return ($condition)?!

* Your function doesn't really work as expected:

// $_SERVER['HTTP_REFERER'] = 'www.yourdomain.com.myowndomain.com';

if (ValidateReferer('yourdomain.com')) {
echo 'Validated!';
}


Output:

Validated!


Why not explode the referring domain by the dot sign? then check the array for www.

i.e.
$str_referring_domain = $_SERVER['HTTP_REFERRER'];

$array_domain_parts = explode(".", $str_referring_domain);
foreach($array_domain_parts as $part)
{
if(strtolower($part) == "www")
{
//Whatever you're going do do here
}
}

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Yogurt? I hate yogurt! Even with strawberries!